Buzzstormer: Difference between revisions
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'''Buzzstormer''' is a 2-vs.-2 [[minigame]] in ''[[Mario Party 7]]''. Its name is possibly a pun on "brainstormer." It takes place in an oversized meadow | '''Buzzstormer''' is a 2-vs.-2 [[minigame]] in ''[[Mario Party 7]]''. Its name is possibly a pun on "brainstormer." It takes place in an oversized meadow. | ||
==Introduction== | ==Introduction== | ||
Revision as of 21:02, October 24, 2022
| Buzzstormer | |||
|---|---|---|---|
| |||
| Appears in | Mario Party 7 | ||
| Type | 2-vs.-2 minigame | ||
| Initial record | 1'00"00 | ||
| Music track | Don't Look Down | ||
| |||
Buzzstormer is a 2-vs.-2 minigame in Mario Party 7. Its name is possibly a pun on "brainstormer." It takes place in an oversized meadow.
Introduction
The first team is shown flying in its aircraft towards a dandelion, then the team turns right to avoid it. The screen then splits in two to show the other team as the minigame starts.
Gameplay
In this minigame, both teams of players are in large bee-like aircraft and need to get through a forest of large dandelions. Hitting a dandelion's stem will paralyze a team's aircraft for a few seconds, giving the other team a chance to get ahead. The first team to get to the end of the dandelions is greeted by a large cliff and an open field and wins the minigame. If five minutes pass without either side crossing the finish line, the minigame ends in a tie.
Ending
The winning team continues flying in its aircraft while the two team members wave.
Controls
– Move
In-game text
- Rules – "Move left and right to avoid the dandelions."
- Advice – "Move in the same direction as your partner to make the bee tilt more."
Names in other languages
| Language | Name | Meaning | Notes |
|---|---|---|---|
| Japanese | おはなばたけレース[?] Ohanabatake rēsu |
Flower Garden Race | |
| German | Summerbrummer[?] | ? | |
| Italian | Fiori traditori[?] | Traitor flowers | |
| Spanish | Carrera de abejas[?] | Bee Race |
Trivia
- If the team does not hit anything, then the team is guaranteed to get a time of 19"45 (in the NTSC/60Hz version)/23"34 (in the PAL/50Hz version). In both cases, it is equivalent to 1,167 frames.
